英国高中数学题(a+3x)^5 the coefficient of the term in x^2 is eight
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英国高中数学题
(a+3x)^5 the coefficient of the term in x^2 is eight times the coeffient of the term in X find the value of the constant a
怎么做 谢谢。 请写出过程 答案是0.75 但是我不知道怎么做的
(a+3x)^5 the coefficient of the term in x^2 is eight times the coeffient of the term in X find the value of the constant a
怎么做 谢谢。 请写出过程 答案是0.75 但是我不知道怎么做的
题目的中文意思是:
(a+3x)^5的x^2项系数是x项系数的8倍,求常数a的值
由二项式定理,x^2项的系数为C(5,2)*a^3*(3)^2,x项系数为C(5,1)*a^4*(3),由倍数关系列等式可得a=0.75
(a+3x)^5的x^2项系数是x项系数的8倍,求常数a的值
由二项式定理,x^2项的系数为C(5,2)*a^3*(3)^2,x项系数为C(5,1)*a^4*(3),由倍数关系列等式可得a=0.75
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