如图,AB‖CD,AD、BC相交于点O,若OA = 2,OD = 4,AB = 3.
如图,AB‖CD,AD、BC相交于点O,若OA = 2,OD = 4,AB = 3.
如图,AD、BC相交于点O,OA=OD,AB//CD.求证:AB=CD
如图,AC与BD相交于点O,已知AB=CD,AD=BC,说明OA=OC,OB=OD的理由
已知:如图,AB平行CD,AD与BC相交于点O,且OA=OD.求证OB=OC
如图,AD和BC相交于点O,OA=OD,OB=OC.求证AB平行DC?
如图,AB,CD相交于点O,AC||BD,求证OA*OD=OB*OC
如图,已知AD、BC交与点O,AB∥CD,OA=OD,求证:AB=CD
如图,已知AB‖CD,BC/EF相交于点O,OA=OD,AE=DF,求证:EB‖CF
如图AD,BC相交于点O,且OA=OC,OB=OD EF过点O分别交AB,CD于点E,F且∠AOE=∠COF.求证OE=
如图,AB.CD相交于点O,且AB=CD.AD=CB证明OB=OD
如图,已知AB,cD相交于点O,且AB=cD,AD=CB,求证OB=OD
如图,已知AB,CD相交于点O,且AB=CD,AD=CB.求证:OB=OD