函数y=arctan(1+x^2)求dy/dx

函数y=arctan(1+x^2)求dy/dx 设函数y=arctan(1+x^2),求dy/dx. 已知函数arctan(y/x)=ln√((x∧2)+(y∧2)),求dy/dx x^2+y^2=e^(arctan（y/x）),求dy/dx y=arctan(x+1)^1/2,求dy=? 设x=t+arctan t+1,y=t的立方+6t－2,求dy／dx 已知函数y(x)由方程arctan y/x=1/2ln(x^2+ y^2)确定,求dy. 设参数方程式 {x=ln(1+t^3) y=t-arctan t ;确定y是X的函数,求 dy/dx? 1,y=e^tanxcos^3x,求dy 2,函数y=y（x）由方程e^(x+y)+arctan(xy)=0确定,求dy 计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y 对于等式arctan（y/x）=ln(sqrt(x^2=y^2)),用matlab求:dx/dy. y=arctan(1-x/1+x),求dy