int a[4][10],*p
int a[4][10],*p
fun ( int *p ) { int a=10; p = &a; ++a; } main ( ) { int a=5
int *p,a[10]; for(p=a;p
int a [4][10] ,*p; p=a;这句话为什么错了啊?int a[9],*p; p=a;和上面的区别?
int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)
int a[10],*p=a;则p+4表示什么?
struct m { int x; int *y; }*p; int a[4]={12,13,-40,100};
int a[]={5,10,15,20,25,30}; int b=LA(a,4); int c=LA(a+2,3);p
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
main() {int a【5】={2,4,6,8,10},*p,**k; p=a;k=&p;
main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf("%d"
有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5