dy/dx=3x^2-8x+100 求y=?

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/06/06 12:08:30

y=x^3-4x^2+100x
再问：跪求步骤
再答：三个分开，一个一个来 d(x^3)/dx=3x^2 d(x^2)/dx=2x dx/dx=1 所以dy/dx=d(x^3)/dx-4*[d(x^2)/dx]+100*(dx/dx) dy=d(x^3)-4*d(x^2)+100*dx=d(x^3-4x^2+100x ) y=x^3-4x^2+100x

dy/dx=3x^2-8x+100 求y=? 求dy/dx=(x-y+5)/(x+y-2) x^2+xy+y^3=1,求dy/dx dy/dx-y/x=x^2 (x^2)dy+（y^2)dx=dx-dy y=2x^2+x求dy/dx x=sin(y/x)+e^2 求dy/dx y=e^x/x^2+sin2x 求dy/dx dy/dx=-x/y 求通解求dy/dx= - x/y y=(sinx)^x 求DY/DX y=x+lnx,求dx/dy