1*2*3···2008*2009*(-1)*(-1/2)*(-1/3)···(-1/2008)*(1/2009)
1*2*3···2008*2009*(-1)*(-1/2)*(-1/3)···(-1/2008)*(1/2009)
1/2009×2/2009×3/2009×4/2009×5/2009×······×2008/2009怎么算?
(1+3+5······+2007+2009+2011)-(2+4+6+·····+2006+2008+2010)
计算1+2-3-4+5+6-7-8+······+2005+2006-2007-2008+2009
计算 1*2/1+2*3/1+3*4/1+············+2009*2010/1
请问(2/2009+4/2009+6/2009+···+2008/2009)—(1/2009+3/2009+5/2009
1-2+3-4+5-6+·····+2008-2009=?··· 十分钟内给我答案
在1×2×3×·······×2008×2009中,它是2009个连续自然数的乘积,其末尾连续有几个0?
计算: 1-2=3-4+5-6+···+2007-2008-2009=
1+2-3-4+5+···+2007+2008-2009-2010+2011
小学六年级数学2/(1/3)+2/(2/3)+2/(3*4)+······+2/(2008*2009)=?
1+2++3+··········+10000=