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来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/26 01:34:29

【详情请点开( ^ ^) _U~
全文是：

lim(x-> π/2) (lnsinx)/( π-2x)^2 (0/0)
=lim(x-> π/2) [-cosx/sinx]/[-4(π-2x)]
=(1/4)lim(x-> π/2) cotx/(π-2x) (0/0)
=(1/4)lim(x-> π/2) -(cscx)^2/(-2)
=(1/8)lim(x-> π/2) (cscx)^2
=1/8

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