1.x-z/xy - 2ab/xy
1.x-z/xy - 2ab/xy
初二数学分式的加减法1.x-z/xy - 2ab/xy 2.a²+b²/a-b - 2ab/a-b
(2X+Z-Y)/(X^2-XY+XZ-YZ)-(Y-Z)/(X^2-XY-XZ+YZ)
求(2X+Z-Y)/(X^2-XY+XZ-YZ)-(2X+Y+Z)/(X^2+XY+XZ+YZ)
已知X:Y:Z等于3:4:5,求2XY-3XY+Z的平方除以X平方减2XY减Z平方
因式分解x²-y²-z²+2xy
证明 (x+y+z)^2>3(xy+yz+zx)
求方程组x+y=2xy−z
设Z=x²+2xy,求dz
-2(-3xy+2z)+3(-2xy-5x)先去括号,在合并同类项
(-3/2xy)(-x²z)(5xy²)
(1/x+1/y+1/z)×(xy)/(xy+yz+zx)