lingo运行出错model:sets:points/1..24/:d;endsetsmax=@sum(points(i

来源：学生作业帮编辑：作业帮分类：综合作业时间：2024/05/21 18:36:01

lingo运行出错
model:sets:points/1..24/:d;endsetsmax=@sum(points(i):@log(1+(d(i+1)-d(i)+(d(i)^2+d(i+1)^2-2*d(i)*d(i+1)*@cos(3.1415926/6))^(1/2))/(2*d(i)));@for(points(j):d(j)#lt#d(j+1));@for(d(1)#gt#1);@for(points(i):d(i)#gt#d(i+12)+2);end运行有错,是什么原因?求指教,急!
model:
sets:
points/1..24/:d;
endsets
max=@sum(points(i)|i#le#23:@log(1+(d(i+1)-d(i)+(d(i)^2+d(i+1)^2-2*d(i)*d(i+1)*@cos(3.1415926/6))^(1/2))/(2*d(i))));
@for(points(j)|j#le#23:d(j)1);
@for(points(i)|i#le#12:(d(i)+2)20);
end
我修改后的,这里错误怎么解决,谢谢!

挤在一起不错才怪.比如前面endsetsmax
很显然endesets一行,回车之后再max,你连一块必须错嘛.
再问：这是复制时的问题，运行时没有挤在一起，你可以自己试运行一下就知道了
再答： sets:points/1..24/:d; endsets @for(points(j)|j#lt#24:d(j)1.0001; @for(points(i)|i#lt#24:d(i)>d(i+1)+2.0001); max=@sum(points(i)|i#lt#24:@log(1+(d(i+1)-d(i)+(d(i)^2+d(i+1)^2-2*d(i)*d(i+1)*@cos(3.1415926/6))^(1/2)))/(2*d(i))); 其中max少了一个括号，我不知道放在哪里，你自己改一下max这一句。
再问：嗯，括号改过来了，但又有问题 model: sets: points/1..24/:d; pp/1..23/:c; endsets max=@sum(points(i):@log(1+(d(i+1)-d(i)+(d(i)^2+d(i+1)^2-2*d(i)*d(i+1)*@cos(3.1415926/6))^(1/2))/(2*d(i)))); @for(points(j):d(j)#lt#d(j+1)); @for(points:d(1)#gt#1); @for(points(i):d(i)#gt#(d(i+12)+2)); end Error Code 15：No relational operator found 这改怎么改？谢谢！
再答：为什么那么想用#lt#呢，这个不能在：后面出现的。 #lt#的用法是约束i，j之类的，只能 @for(points(j)|j#lt#24:d(j)

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