化简sin(θ-5π)cos(π/2+θ)cos(4π-θ)/cos(3π-θ)sin(θ-3π)sin(-θ-4π)
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
化简sin(θ-5π)cos(π/2+θ)cos(4π-θ)/cos(3π-θ)sin(θ-3π)sin(-θ-4π)
1.已知2sin(3π+θ)=cos(π+θ),求2sin
已知sin(θ+kπ)=2cos[θ+(k+1)π],k∈Ζ,求4sinθ-2cosθ/5cosθ+3sinθ的值
证明下列恒等式: (1)2sin(2/π+x)cos(2/π-x)*cosθ+(2cos^2x-1)*sinθ=sin(
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
化简:[(1+sinθ+cosθ)(sinθ/2-cosθ/2)]/√(2+2cosθ)(0<θ<π)
怎样用matlab解三角函数cos(π/2*cosθ)/sin(θ)=0.707?
若2sin(π4+α)=sin θ+cos θ,2sin2β=sin 2θ,求证:sin&
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小