求解初中数学题（x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y

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求解初中数学题（x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y)求解因式分解法.八年级数学.谢

（x-y)-2(y-x)
=(x-y)+2(x-y)
=3(x-y)
=3x-3y
2(x-y)-8(y-x)
=2(x-y)+8(x-y)
=10(x-y)
=10x-10y
x(a-3)-(3-a)
=x(a-3)+(a-3)
=(a-3)(x+1)
(x2-y2)-3(x+y)
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)

求解初中数学题（x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2 因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)( (2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y) 3a(x-y)+9(y-x 有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【- [(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y) 化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方【x-3y][x+y]-[x-2y][x +2y]-[x-y 若A｛（X,Y)｜Y=x2-2｝,B｛（X,Y)｜X=Y2-2｝,求A∩B 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 求解;一 (x-8y)(x-y) 二 (Y+2)(Y-2)-(Y-1)(Y+5) 三 (3X+4)(3X-4)-(2X+