先化简后求值.((m-n)/(m^2-2mn+n^2)-(mn+n^2)/(m^2-n^2))×(m+1)/(n-1)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/25 04:35:32
先化简后求值.((m-n)/(m^2-2mn+n^2)-(mn+n^2)/(m^2-n^2))×(m+1)/(n-1) 其中m=1/根3-2 n=1/根3+2
((m-n)/(m^2-2mn+n^2)-(mn+n^2)/(m^2-n^2))×(m+1)/(n-1)
=((m-n)/(m-n)^2-n*(m+n)/(m^2-n^2))×(m+1)/(n-1)
=(1/(m-n)-n/(m-n))×(m+1)/(n-1)
=((1-n)/(m-n))×(m+1)/(n-1)
=(-(n-1)/(m-n))×(m+1)/(n-1)
=-(m+1)/(m-n)
=-((1/3^0.5-2)+1)/((1/3^0.5-2)-(1/3^0.5+2))
=-(1/3^0.5-2+1)/(1/3^0.5-2-1/3^0.5-2)
=-(1/3^0.5-1)/(-4)
=(1/3^0.5-1)/4
=((m-n)/(m-n)^2-n*(m+n)/(m^2-n^2))×(m+1)/(n-1)
=(1/(m-n)-n/(m-n))×(m+1)/(n-1)
=((1-n)/(m-n))×(m+1)/(n-1)
=(-(n-1)/(m-n))×(m+1)/(n-1)
=-(m+1)/(m-n)
=-((1/3^0.5-2)+1)/((1/3^0.5-2)-(1/3^0.5+2))
=-(1/3^0.5-2+1)/(1/3^0.5-2-1/3^0.5-2)
=-(1/3^0.5-1)/(-4)
=(1/3^0.5-1)/4
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