2+4+6+8+10.+2n=
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
M=(N-1)×1+(N-2)×2+(N-3)×4+(N-4)×8+(N-5)×16+(N-6)×32+(N-7)×64
main( ) { int n; ( n=6*4,n+6),n*2; printf(“n=%d\n”,n); } 此
如果正整数n使得[n/2]+[n/3]+[n/4]+[n/5]+[n/6]=69,则n=
如果正整数n使得[n/2]+[n/3]+[n/4]+[n/5]+[n/6]=69,则n为( ).([ n ]表示不超过n
16n^a+4n^3+6n^2+7^n=0,求n
简算:[(1*2*4+2*4*8+L+n.2n.4n)/(1*3*9+2*6*18+L=n.3n.9n)]^2
简算:1.[(1*2*4+2*4*8+L+n.2n.4n)/(1*3*9+2*6*18+L=n.3n.9n)]^22.(
(2^n+4^n+6^n+8^n)^(1/n)当n趋于无穷时的极限
用数学归纳法证明:12×4+14×6+16×8+…+12n(2n+2)=n4(n+1)(其中n∈N*).
证明:1+2C(n,1)+4C(n,2)+...+2^nC(n,n)=3^n .(n∈N+)
1\n(n+3)+1\(n+3)(n+6)+1\(n+6)(n+9)=1\2 n+18 n为正整数,求n的值