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当x=2007,y=2008时,代数式x&sup4-y&sup4/x²-2xy-y² ÷x²+y

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/15 18:50:28
当x=2007,y=2008时,代数式x&sup4-y&sup4/x²-2xy-y² ÷x²+y²/y-x的值为
当x=2007,y=2008时,代数式 (x的四次方-y的四次方)/(x²-2xy-y²) ÷(x²+y²)/(y-x)的值为
(x^4-y^4)/(x²-2xy-y²) ÷(x²+y²)/(y-x)
=(x²-y²)(x²+y²)/(x-y)^2÷(x²+y²)/(y-x)
=(x²-y²)*(x²+y²)*(y-x)/(x-y)^2*(x²+y²)
=(x²-y²))/(y-x)
=(x-y)*(x+y)/(y-x)
= --(x+y)
= --x--y
又x=2007,y=2008,所以 (x^4-y^4)/(x²-2xy-y²) ÷(x²+y²)/(y-x)= --x--y= --4015