b^3n-1/a^2n-1×c÷b^3n-2/a^2n
b^3n-1/a^2n-1×c÷b^3n-2/a^2n
计算:b^(3n-1)/a^(2n-1)×c÷b^(3n-2)/a^2n
b^3n-1 c^2/a^2n+1×a^2n-1/b^3n-2=
分式计算:(b^3n-1 )*c/(a^2n+1)除以 (b^3n-2)/(a^2n)
a^(n+1)b^n-4a^(n+2)+3ab^n-12a^2
定义数列An=x^n+y^n+z^n,则A(n+3)-3A(n+2)+b*A(n+1)-c*An=0
a(n+1)=2an-a(n-1) 3bn-b(n-1)=n
已知n为大于1的自然数,计算b^3n-1c^3/a^2n+1 *a^2n/b^3n-2
A.3M+N B.2M+2N C.M+N D.M+3N
两个共点力的大小分别是3N、4N,它们的合力不可能是 A、1N B、2N C、7N D、9N
已知1/n^2+3n=A/n+B/n+3,求ab?
计算 :(-0.5a^3b^2)(-4a^n+1 b^n c) 急