已知抛物线y=ax2+bx+c
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/04/28 15:17:16
var SWOC = {}; SWOC.tip = false; try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.php?qid=594185")}catch(o){if(!oldalert){var oldalert=true;var sys={};var ua=navigator.userAgent.toLowerCase();var s;(s=ua.match(/msie ([\d.]+)/))?sys.ie=s[1]:0;if(!sys.ie){alert("因浏览器兼容问题,导致您无法看到问题与答案。请使用IE浏览器。")}else{SWOC.tip = true;/*if(window.showModalDialog)window.showModalDialog("include\/addsw.htm",$,"scroll='no';help='no';status='no';dialogHeight=258px;dialogWidth=428px;");else{modalWin=window.open("include\/addsw.htm","height=258px,width=428px,toolbar=no,directories=no,status=no,menubar=no,scrollbars=no,resizable=no ,modal=yes")}*/}}}
解题思路: 利用图象上的点满足函数关系式来求出解析式
解题过程:
var SWOC = {}; SWOC.tip = false; try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.php?aid=563394")}catch(o){if(!oldalert){var oldalert=true;var sys={};var ua=navigator.userAgent.toLowerCase();var s;(s=ua.match(/msie ([\d.]+)/))?sys.ie=s[1]:0;if(!sys.ie){alert("因浏览器兼容问题,导致您无法看到问题与答案。请使用IE浏览器。")}else{SWOC.tip = true;/*if(window.showModalDialog)window.showModalDialog("include\/addsw.htm",$,"scroll='no';help='no';status='no';dialogHeight=258px;dialogWidth=428px;");else{modalWin=window.open("include\/addsw.htm","height=258px,width=428px,toolbar=no,directories=no,status=no,menubar=no,scrollbars=no,resizable=no ,modal=yes")}*/}}}
最终答案:略
解题过程:
var SWOC = {}; SWOC.tip = false; try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.php?aid=563394")}catch(o){if(!oldalert){var oldalert=true;var sys={};var ua=navigator.userAgent.toLowerCase();var s;(s=ua.match(/msie ([\d.]+)/))?sys.ie=s[1]:0;if(!sys.ie){alert("因浏览器兼容问题,导致您无法看到问题与答案。请使用IE浏览器。")}else{SWOC.tip = true;/*if(window.showModalDialog)window.showModalDialog("include\/addsw.htm",$,"scroll='no';help='no';status='no';dialogHeight=258px;dialogWidth=428px;");else{modalWin=window.open("include\/addsw.htm","height=258px,width=428px,toolbar=no,directories=no,status=no,menubar=no,scrollbars=no,resizable=no ,modal=yes")}*/}}}
最终答案:略
已知抛物线y=ax2+bx+c
已知抛物线y=3ax2+2bx+c,
已知抛物线y=ax2+bx+c的图象如图所示,
抛物线y=ax2+bx+c(a
已知抛物线y=ax2+bx+c的图像如图所示,则对于一元二次方程ax2+bx+c=0
已知抛物线y=ax2+bx+c与y=−x
已知抛物线y=ax2+bx+c,请分别写出此抛物线关于原点对称的抛物线的解析式.
已知抛物线y=ax2+bx+c,如图所示,直线x=-1是其对称轴,
已知抛物线y=ax2+bx+c经过原点和第二、三、四象限
已知抛物线y=ax2+bx+c,经过(0,1)和(2,-3)两点.
已知抛物线y=ax2+bx+c过三点:(-1,-1)(0,-2)(1,1)
如图,已知抛物线y=ax2+bx+c经过O(0,0)