求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/16 01:53:17

换底公式
原式=(lg3/lg4+lg3/lg8)(lg2/lg3+lg4/lg3)-log2(2^6)
=(lg3/2lg2+lg3/3lg2)(lg2/lg3+2lg2/lg3)-log2(2^6)
=[(1/2+1/3)(lg3/lg2)][(1+2)(lg2/lg3)]-6log2(2)
约分
=(1/2+1/3)(1+2)-6
=5/2-6
=-7/2

求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) 利用换底公式求值：1.log2 25 ×log3 4 ×log5 9 2.（log4 3+log8 3）（log3 2+ 1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 求值(log4(3)+log8(3))×(log3(2)+log9(2)) 求值(log3(2)+log9(2))*(log4(3)+log8(3)) (log3 2+log9 2)*(log4 3+log8 3)求值求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16) log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^ (log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32 (log4(3)+log8(3))*log3(2) (log3^2 + log9^4)×(log4^3 + log8^3) (log4 3+log8 3)*(log3 2+log4 2)