∵(2x-1)+i=y-(3-y)i(2x+ay)-(4x-y+b)i=9-8i,∴
∵(2x-1)+i=y-(3-y)i(2x+ay)-(4x-y+b)i=9-8i,∴
已知关于x,y的方程组2x-1+i=y-(3-y)i和2x+ay-(4x-y+b)i=9-8i有实数解,求实数a,b的值
已知关于x,y的方程组(2x-1)+i=y-(3-y)i,(2x+ay)-(4x-y+b)i=9-8i有实数解,求a,b
1、已知关于X、Y的方程组(2x+1)+i=y+(3-y)i (2x+ay)+(y-4x-bi)=9-8i有实数解,求a
(3x+2y)+(5x-y)i=17-2i.求x与y
若全集I={(x,y)|x,y∈R},集合M={(x,y)|(y-3)/(x-2)},N{(x,y)|y=x=1},则(
已知,I x I+I 3y-8 I+I z-2 I = 0,求代数式x+3y+z的值?
已知集合A={(x,y)| (y-3)/ (x-1)=2,x,y∈R},B={(x,y)| 4x+ay=16,x,y∈
# define MA(x,y) (x)*(y) int i=2; i=3/MA(i,i+2)+5; printf(“%
【复数】(1+i)x+(1-i)y=2,则x=?,y=?
l x-3l与I 2y+3I互为相反数则x+y=
求适合下列条件的实数x和y的值:1、(3x+2y)+(5x-y)i=17-2i;2、(3x-4y)+(2y+3)i=0