vf题 set talk off s=0 x=2 y=5 do RR “s=”,s return

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vf题 set talk off s=0 x=2 y=5 do RR “s=”,s return
vf题
set talk off
s=0
x=2
y=5
do RR
“s=”,s
return
*RR.prg
x=y
s=s+x
retrun
答案是s=2

晕死,答案是5,不是2set talk off
s=0
x=2
y=5
do RR   &&此时,s=0,x=2,y=5,前往执行过程注1
?“s=”,s   &&此时,s=5,x=5,y=5 ,见注3
return

proc rr
x=y     &&此时,s=0,x=5,y=5  注2
s=s+x   &&此时,s=5,x=5,y=5  注3
  retu
再问：为什么x=y=5而不是x=y=2
再答：这其实是一种很简单的等量代换。 y=5, x=y 那么x=5. 在电脑上，可以对变量赋值，但如果对变更重新赋值，原变量的值将被覆盖。本例中， x=2,这是赋初值。但后面，X被重新赋值，其初值即被覆盖了，不再为2，而为新值5了

vf题 set talk off s=0 x=2 y=5 do RR “s=”,s return VFP：set talk off clear s=0 for m=3 to 7 n=2 do while n SET TALK OFF CLEAR STORE 0 TO S,T,P FOR K=1 TO 10 DO ... SET TALK OFF CLEAR STORE 0 TO S,T,P FOR K=1 TO 10 DO CASE CA SET TALK OFF,X=2 ,DO WHILE X 一道VF题求答案SET TALK OFFCLEARSTORE 0 TO X,YDO WHILE .T.X=X+1DO C vfp程序解答,set talk off,s=0,for i=1 to 10,i=i+1,s=s+i,endfor,?s set talk off clear s=o i=1 最好带中文的 SET TALK OFF CLEA S=0 FOR I=1 TO 10 STEP 1 S=S+I I=I+1 ENDF 求讲解一道VF的题目有如下程序 SET TALK OFF DIMENSION K(2,3) I=1 DO WHILE I VF题：SET TALK OFF STORE 1 TO I,J FOR N=1 TO 4 @I,J+1 SAY“AB” 用MATLAB求出G(s)=(s*s+2s+2)/(s*s*s*s+7s*s*s+3s*s+5s+2)的极点