1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/04 13:25:45

1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)
=[1/x-1/(x+3)+1/(x+3)-1/(x+6)+1(x+6)-1/(x+9)]/3
=[1/x-1/(x+9)]/3
=3/x(x+9)
=3/2x+18
2x+18=x(x+9)
x²+7x-18=0
(x-2)(x+9)=0
x1=2x2=-9(经检验知,不合舍去）
所以,x=2是原分式方程的解

|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), x+2/x^2-x-6 + 2x/x^3-3x - x+1/x^2-6x+9 (x+2/x^2-x-6)-(2x/x^2-3x)-(x+1/x^2-6x+9) （1） x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8 1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18 2x/x^2-9=x-1/x^2-6x+9-1/x+3 (x-2)(x2-6x-9)-x(x-5)(x-3)其中x= -1/3 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550 1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980