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请matlab高手来帮忙 自变量x取值范围[60°,130°],y=arccos((129.6+188.16cos(x)

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/27 07:13:07
请matlab高手来帮忙 自变量x取值范围[60°,130°],y=arccos((129.6+188.16cos(x)-155.82sin(x))/250.9)
z=2arctan((-6.5sin(y)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y)+14.7cos(x)))
t=19.3cos(z)+1.6746(19.3cos(z)-14.7cos(x)+7.06729)
求t-x变化曲线
如果z=2arctan((-6.5sin(y-z)+14.7sin(x)+4.370746)/(12.23271-6.5cos(y-z)+14.7cos(x)))
x=60:130;
x=x/180*pi;
y=acos((129.6+188.16.*cos(x)-155.82.*sin(x))/250.9);
z=2*atan((-6.5.*sin(y)+14.7.*sin(x)+4.370746)/(12.23271-6.5.*cos(y)+14.7.*cos(x)));
 t=19.3.*cos(z)+1.6746.*(19.3.*cos(z)-14.7.*cos(x)+7.06729);
plot(x,t)