log₂9÷log₂3=?请说下过程,
log₂9÷log₂3=?请说下过程,
log₂3×log₃4+﹙√3﹚∧log₃4=
log₂log₃log₄ X=log₃log₄logS
化简:log₂12-log₂3
求log₂25×log₃2√2×log(5)9的结果,
log(2)(25)*log(3)(根号2)*log(5)(9)
log(2)9×log(3)4
log(2)9log(3)4等于
log以2为底3*log以9为底8=说明过程
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路