求证:sinx/x>(cosx)^(1/3) (0
求证:sinx/x>(cosx)^(1/3) (0
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
已知x∈(0,π/2),求证:sinx+cosx>1
3sinx-2cosx=0 (1)(cosx-sinx)/(cosx+sinx)+(cosx+sinx)/(cosx-s
:求证:sinx-cosx分之sin平方x - tan平方x-1分之sinx+cosx=sinx+cosx
求证:当x>0时,不等式sinx+cosx>1+x-x^2成立.
如题,求证:sin2x/ [(sinx+cosx-1)(sinx+1-cosx)] =cot(x/2)
求证:tan(x/2)=(1-cosx+sinx)/(1+cosx+sinx)
求证:(1+sinx-cosx)/(1+sinx+cosx)=tan(x/2)
求证:tan(x/2)= sinx/(1+cosx)=(1-cosx)/sinx
求证:tan(x-π/4)=(sinx-cosx)/(sinx+cosx)
求证!(1 + cosx )/sinx = cot(x/2)