怎么用MATLAB画出B=2*2^(1/2)*μ0*a^2/[pi*(a^2+4z^2)*(a^2+2z^2)^(1/2
怎么用MATLAB画出B=2*2^(1/2)*μ0*a^2/[pi*(a^2+4z^2)*(a^2+2z^2)^(1/2
设复数z=a+bi(a,b∈R,b>0),z^2/(1+z)和z/(1+z^2)均为实数.求z
求积分计算f{|z|=pi}(z/(z+1))*(e^(2/(z+1)))dz
若复数z=1+i,且实数a,b满足az+2b.z=(a+2z)
若a-2i=bi+1(a、b∈R),复数z=b+ai,则z.z
matlab中t=(0:a)/a*2*pi是什么意思?
已知|Z-1|=2,arg(Z-1)的3Pi/2,求复数Z
matlab >> syms x y z a b cy=16.7143*x^2-46.227*x+36.3129;z=0
matlab这公式怎么输入 a=arctan(y/x) b=1/2[pi/2-arctan(y/x) a+2b=pi/2
已知复数z满足:/z/=1+3i-z 求z 设z=a+bi /z/=1+3i-z=根号<a^2+b^2>=1-a+<3-
已知z^2/(1+z)和z/(1+z^2)都为实数,则复数z=a+bi为
设复数z=a+i,绝对值z等于根号2,求复数z,和z+1分之z格玛