用java写一个程序把24小时制的时间转换为12小时制的时间.具体说明内详

用java写一个程序把24小时制的时间转换为12小时制的时间.具体说明内详
下面是示例对话过程:
Enter time in 24-hour notation:
13:07
That is the same as
1:07 PM
Again?(y/n)
y
Enter time in 24-hour notation:
10:15
That is the same as
10:15 AM
Again(y/n)
y
Enter time in 24-hour notation:
10:65
There is no such time as 10:65
Try again:
Enter time in 24-hour notation:
16:05
That is the same as
4:05 PM
Again?(y/n)
n
End of program
要定义一个名为TimeFormatException的异常类.如果用户输入了不合法的时间,比如10:65,甚至是无意义的东西,比如8&*68,程序将会抛出、捕获并处理一个TimeFormatException

你看一下,这个是不是你想要的,
import java.text.SimpleDateFormat;
import java.util.Locale;
import java.util.Scanner;
public class App {
public static void main(String[] args) {
while (true) {
System.out.println("Enter time in 24-hour notation:");
Scanner sc = new Scanner(System.in);
String line = sc.nextLine();
try {
outTime(line);
} catch (TimeFormatException e) {
System.out.println("There is no such time as " + line);
System.out.println("Try again:");
continue;
}
sc = new Scanner(System.in);
line = sc.nextLine();
if ("n".equalsIgnoreCase(line)) {
break;
}
}
System.out.println("End of program");
}
public static void outTime(String line) throws TimeFormatException {
SimpleDateFormat _24time = new SimpleDateFormat("HH:mm");
SimpleDateFormat _12time = new SimpleDateFormat("hh:mm a",
Locale.ENGLISH);
try {
String[] array = line.split(":");
if (Integer.parseInt(array[0]) < 0
|| Integer.parseInt(array[0]) > 23) {
throw new TimeFormatException();
}
if (Integer.parseInt(array[1]) < 0
|| Integer.parseInt(array[1]) > 59) {
throw new TimeFormatException();
}
System.out.println(_12time.format(_24time.parse(line)));
System.out.println("Again?(y/n)");
} catch (Exception e) {
throw new TimeFormatException();
}
}
}
class TimeFormatException extends Exception {
}