come in and have a look
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 02:56:22
come in and have a look
A B C D
_____×9
D B C A
ABCD×9=DCBA
A B C D 分别为 一个数字.
求A B C D四个数字为?
A B C D
_____×9
D B C A
ABCD×9=DCBA
A B C D 分别为 一个数字.
求A B C D四个数字为?
ABCD
× 9
DCBA
因DCBA仍是四位数
所以A必是1,
否则ABCD×9不会是四位数
又因D×9的个位数字是1,
所以D必是9
将算式写为
1 BC9
× 9
9CB 1
因为B×9没有进位(否则A×9+进位积就不是四位数)
所以B必然是0(因A=1)
又因C×9+8的个位数字是0,
所以C必然是8
即ABCD=1089
验算:1089×9=9801
好运
× 9
DCBA
因DCBA仍是四位数
所以A必是1,
否则ABCD×9不会是四位数
又因D×9的个位数字是1,
所以D必是9
将算式写为
1 BC9
× 9
9CB 1
因为B×9没有进位(否则A×9+进位积就不是四位数)
所以B必然是0(因A=1)
又因C×9+8的个位数字是0,
所以C必然是8
即ABCD=1089
验算:1089×9=9801
好运
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