作业帮dim m(5,5),s(5) for i=1 to 5 s(i)=0 for j=1 to 5 m(i,j)=i+j
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dim m(5,5),s(5) for i=1 to 5 s(i)=0 for j=1 to 5 m(i,j)=i+j s(i)=s(i)+m(i,j) next j next i
for each x in s
print x;
next x
这个题的最终答案是20 25 30 35 40
所不理解是就是关于问题补充部分中for each x in
for each x in s
print x;
next x
这个题的最终答案是20 25 30 35 40
所不理解是就是关于问题补充部分中for each x in
s是一个数组
for each x in s
print x
next
和
for i=1 to ubound(s)
x=s(i)
print x
next i
结果是一样的
for each x in s,从s的第一个元素开始,x就表示s的一个元素s(i),直到最后一个元素
for each x in s
print x
next
和
for i=1 to ubound(s)
x=s(i)
print x
next i
结果是一样的
for each x in s,从s的第一个元素开始,x就表示s的一个元素s(i),直到最后一个元素
dim m(5,5),s(5) for i=1 to 5 s(i)=0 for j=1 to 5 m(i,j)=i+j
s=0,for i=1 to 5,for j=1 to i,for k=j to 4,s=s+1,next k,next
for(j=i+n+1; j>i; j--)和s[j+1]= s[j];
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for(j=i;j>0;j--)
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下面语句执行后,i 的值是( B ).for( int i=0,j=1; j < 5; j+=3 ) i=i+j; A)
main() {long m,n,i=1,j,s; scanf("%ld,%ld",&m,&n); for(;i