用加减法解{2X+3Y+Z=38 3X+4Y+2Z=56 4X+5Y+Z=66
用加减法解{2X+3Y+Z=38 3X+4Y+2Z=56 4X+5Y+Z=66
用加减法解三元一次方程组 2x+3y+z=38 3x+4y+2z=56 4x+5y+z=66
用加减法解下列方程组:{2x+3y+z=38,3x+4y+2z=56,4x+5y+z=66
解方程组:x+y+z=4,x+y+2z=5,3x+y-z=6
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
解方程组:2x+3y+z=38,3x+4y +2z=56,4x+5y+z=66
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
用加减法 解3元一次方程组y=2x-7 5x+3y+2z=2 3x-4z+4
x/2=y/3=z/5 x+3y-z/x-3y+z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解方程:{2x+3y+z=7,x+y+z=4,3x+y-z=-4