from ground level,a ball is thrown upward with an initial ve
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from ground level,a ball is thrown upward with an initial velocity of 83.3m/s When will the ball reach a height of 294m?
s = ut + 1/2 at^2
with this equation,you can find the time for the ball to reach the height of 294m.
s is the distance 294m
u is the initial velocity 83.3m/s
a is the acceleration due to gravity,in this case is negative.9.81
t is the time you want to find.\
the answer has two value since its an quadratic equation.one of the answer is the time taken for the ball to reach the height of 294m another one is the time taken for the ball reach 294m again,but falling down.
with this equation,you can find the time for the ball to reach the height of 294m.
s is the distance 294m
u is the initial velocity 83.3m/s
a is the acceleration due to gravity,in this case is negative.9.81
t is the time you want to find.\
the answer has two value since its an quadratic equation.one of the answer is the time taken for the ball to reach the height of 294m another one is the time taken for the ball reach 294m again,but falling down.
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