数列an前n项和sn,数列bn中b1=a1,bn=an-a(n-1)(n>=2),若an+sn=n(1)设cn=an-1
数列an前n项和sn,数列bn中b1=a1,bn=an-a(n-1)(n>=2),若an+sn=n(1)设cn=an-1
数列{An}的前n项和是Sn,数列{Bn},B1=A1,Bn=An-A(n-1),An+Sn=n,Cn=An-1,证{C
数列{an}的前n项和为Sn,数列{bn}中,b1=a1,bn=an-an-1(n≥2),若an+Sn=n.
设数列{an}的前n项和为Sn=2an-4,bn=log2an,cn=1/bn^2,求证:数列{an}是等比数列?
已知数列an bn其中a1=1/2数列an的前n项和Sn=n^2an(n≥1) 数列bn满足b1=2 bn+1=2bn
设数列an前n项和为Sn,且an+Sn=1,求an的通项公式 若数列bn满足b1=1且bn+1=bn+an,求数列bn通
高二关于等比数列的题数列{an}的前n项和为Sn,数列{bn}中,b1=a1,bn=an-a(n-1)(n>=2)且an
数列an前n项和为sn,a1=1,数列bn首项b1=2,且sn+n^2=n(an+1),bn=abn-1求an,bn的通
设数列{an}的前n项和为Sn,已知a1=a,an+1=Sn+3^n,n∈N+.设bn=Sn+3n,求数列{bn}的通项
设数列{an}的前n项和为sn,已知a1=a,an+1=sn+3^n,n∈N* (1)设bn=sn-3^n,求数列{bn
数列{an},a1=1,an=2-2Sn,求an,若bn=n*an,求{bn}的前n项和Tn
已知数列{an}中a1=1 a[n+1]=3an 数列{bn}的前几项和Sn=n^2+2n,设cn=an*bn,求Tn=