1×9+2=1112×9+3=111()×9+()=1111()×9+()=11111()×9+()=111111()×
1×9+2=1112×9+3=111()×9+()=1111()×9+()=11111()×9+()=111111()×
9()9()9()9()9=7、9()9()9()9()9=1 填运算符号
1×9+2=11,12×9+3=111,123×9+4=1111,1234×9+5=11111,猜测123456×9+7
加运算符号9 ()9()9()9() 9()=0
1×9+2=11 12×9+3=111 123×9+4=1111 1234×9+5=11111···123456789×
已知1×9+2=11,12×9+3=111,123×9+4=1111,1234×9+5=11111,那么1234567×
1×9+2=11,12×9+3=111,123×9+4=1111,1234×9+5=11111;故答案为:11
按规律填数.1×9+2=11.12×9+3=111.123×9+4=1111.()×9+5
0.5:3分之2=9÷( )=( )%
()÷36=1/3=9:()=12:()=24分之()
2/9:7/9=3/4:(4-x)
75/()=()/40=9:()=3/()=()/16=0.75