log a(1/2次方) x等于2log a
log a(1/2次方) x等于2log a
x=log a 2
[log (底数为a) x]=[1\2log (底数为a) b ] - [ log (底数为a)c]求X
2log(b)x=log(a)x+log(c)x
log(a-1) (2x-1)-log(a-1)(x-1)>0
log(2)(a)>log(1/2)(-a) 解不等式
已知log根号3为底的2次方等于a分之1-a.求log12底3次方
log a(2/3)
log(a)2
若不等式2^x-log(a)(x)
解方程[log(a)(x-1)]-[log(a)(2x-3)]=log(a)(1/3-x),(a>0,且a≠1).
函数y=log以a为底x,当log以a为底(x^2-x+1)小于等于log以a为底3/4成立时,a的取值范围.