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(log8 9/log2 3)=?

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(log8 9/log2 3)=?
方法一
(log8 9/log2 3)
=(lg9/lg8)/(lg3/lg2)
=(2lg3/3lg2)/(lg3/lg2)
=(2/3)*(lg3/lg2)/(lg3/lg2)
=2/3
方法二
(log8 9/log2 3)
=log2^3 3^2/log2 3
=(2/3)log2 3/log 2 3
=2/3
logm^a n^b
=(b/a)logm n
(log8 9/log2 3)=? log8(9)*log2(3) log8(9)除以log2(3) 求(log2^3+log8^9) 已知log2^3=a.则log8^3= log8^9= log8的9次方/log2的3次方= log8^9/log2^3的值是 log8 9/log2 3的值是? log8(9)=a,log2(5)=b,则lg(3)=? (log8 9/log2 3) =(lg9/lg8)/(lg3/lg2) ,这是为什么尼 log8ˇ9除以log2ˇ3 等于? log8 4=?2^(log2 3-2)=?