已知:根号a-1+(ab-2)²=0
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/08 00:52:14
已知:根号a-1+(ab-2)²=0
求:1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008).
求:1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008).
根号a-1+(ab-2)²=0
所以有a-1=0且ab-2=0
得到a=1,b=2
那么,1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008)=1/2*3+1/3*4+.+1/2009*2010
=1/2-1/3+1/3-1/4+.+1/2009-1/2010
=1/2-1/2010
=502/1005
再问: 我出错题了,应该是求:1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)
再答: 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008) =1/1*2+1/2*3+1/3*4+...+1/2009*2010 =1-1/2+1/2-1/3+1/3-1/4+...+1/2009-1/2010 =1-1/2010 =2009/2010
所以有a-1=0且ab-2=0
得到a=1,b=2
那么,1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008)=1/2*3+1/3*4+.+1/2009*2010
=1/2-1/3+1/3-1/4+.+1/2009-1/2010
=1/2-1/2010
=502/1005
再问: 我出错题了,应该是求:1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)
再答: 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2007)(b+2007)+1/(a+2008)(b+2008) =1/1*2+1/2*3+1/3*4+...+1/2009*2010 =1-1/2+1/2-1/3+1/3-1/4+...+1/2009-1/2010 =1-1/2010 =2009/2010
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