4(x+y)^2+25-20(x+y)怎么解,
4(x+y)^2+25-20(x+y)怎么解,
{x-y+(4xy/x-y)}{x+y-(4xy/x+y)}怎么解?
4(x+y)-20(x+y)+25
这题怎么解?X-Y=4,2X+Y=20,X=?Y=?3X+2Y=14,2X-3Y=5,X=?Y=?
1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y
2x+5y=25 4x+3y=15两元一次 怎么解
因式分解:4(x+y)^2+25-20(x+y)
20(x+y)+25+4(x+y)^2
4(x+y)2+25-20(x+y) 因式分解
4(x+y)^2-20(x-y)+25
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20