x(2x-1)2-4(x-3)(x2+3x+9)-(9+2x)(9-2x)=0
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 17:10:46
x(2x-1)2-4(x-3)(x2+3x+9)-(9+2x)(9-2x)=0
x(2x-1)^2 -4(x-3)(x^2 +3x+9)-(2x+9)(9-2x)=0
x(4x^2 -4x+1)-(x^2 +3x+9)(4x-12)-(81-4x^2)=0
4x^3 -4x^2 +x-(4x^3 -12x^2 +12x^2 -36x+36x-108)-81+4x^2=0
4x^3 -4x^2 +x-(4x^3 -108)-9+4x^2=0
(4x^3 -4x^3)-(4x^2 -4x^2)+x+108-81=0
化简得 x=-27
所以 该方程解是x=-27
x(4x^2 -4x+1)-(x^2 +3x+9)(4x-12)-(81-4x^2)=0
4x^3 -4x^2 +x-(4x^3 -12x^2 +12x^2 -36x+36x-108)-81+4x^2=0
4x^3 -4x^2 +x-(4x^3 -108)-9+4x^2=0
(4x^3 -4x^3)-(4x^2 -4x^2)+x+108-81=0
化简得 x=-27
所以 该方程解是x=-27
(x-2)(x2-6x-9)-x(x-5)(x-3)其中x= -1/3
(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
x(2x-1)2-4(x-3)(x2+3x+9)-(9+2x)(9-2x)=0
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?
x · 根号(X2+3X+18) - X · 根号(X2-6X+18)=1 那么2X · 根号(X2-6X+18)-9X
x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x 化简
化简x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8