用待定系数法解这一题2x^2+xy-y^2-4x+5y-6(x^2意为x取消) 千万别就一个答案啊 而且不要是别的办法
用待定系数法解这一题2x^2+xy-y^2-4x+5y-6(x^2意为x取消) 千万别就一个答案啊 而且不要是别的办法
待定系数法因式分解:(1)x方+2xy+y方+x+y-2 (2)x方+xy-2y方+2x+7y-3
x^8-x^7y+x^6y^2-x^5y^3+x^4y^4-x^3y^5+x^2y^-xy^7+y^8
是关于因式分解的``1.计算x×x×x×x+5×x×x-6(x+y)(x+y+2xy)+(xy+1)(xy-1)2.已知
2x^2+xy-y^2-4x+5y-6因式分解的答案
因式分解 求过程 x-xy+3y-3x 2x+xy-y-4x+5y-6
(xy-x^2)乘以(xy)/(x-y)
为什么我约分2x^2y(x-y)^2/12xy^2(y-x)到后面得x(x-y)^2/6y(y-x).而答案是x(y-x
(x^2+xy/x-y)/(xy/x-y)计算
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)