计算:n(n+1)(n+2)(n+3)+1
计算:n(n+1)(n+2)(n+3)+1
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
计算:C(1,n)+2C(2,n)+3C(3,n) + … + nC(n,n)
计算9^n*(1/27)^n+1*3^n+2
2^n/n*(n+1)
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简(n+1)(n+2)(n+3)
n阶行列式计算|1 2 3.n-1 n||2 1 3.n-1 n||2 3 1.n-1 n||.||2 3 4. 1 n
如果,n是大于2的整数,计算1/(n-1)(n-2)+1/(n-2)(n-3)+1/(n-3)(n-4)+……+1/(n
计算1/(m-n)-1/(m+n)-2n/(m^2+n^2)-4n^3/(m^4+n^4)-8n^7/(m^8+n^8)
计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1)