如何将sin(2x)*cos(x)+sin^2(x) 展开为sin(x)的表达式?或者如何化简?
如何将sin(2x)*cos(x)+sin^2(x) 展开为sin(x)的表达式?或者如何化简?
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/2) 化简为sin的形式
cos(x)*(sin(x))^2*d(sin(x)),在0到90的定积分如何计算,
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
化简 cos^2(x)*sin^2(x)-sin^2(x)
化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x)
将表达式COS^2 X+根号3sinxcosx化成SIN(2X+A)
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
∫sin(x) cos^2(x)dx
f(x)=cos2x+2sinx如何化成关于sin或cos的最简形式!
x-sin(x/2)cos(x/2)的导数
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x