x>y>0,xy=1,求证:(x^2+y^2)/x-y)>=2倍根号2
x>y>0,xy=1,求证:(x^2+y^2)/x-y)>=2倍根号2
{(x-y)/(根号x+根号y)}-(x+y-2倍根号xy)/(根号x-根号y)=?
x根号x+x根号y/xy-y^2)-(x+根号xy+y/x根号x-y根号)y
已知x平方+y平方-2y+1=0,求(根号x+根号y+3)/((根号xy+y)(3根号x+根号y))
已知x>y>0,xy=1,求证(x^2+y^2)/(x-y)≥2根号2
已知:x>0,y>0,x-2y=根号xy.求(x+(根号xy)+y)/(x-(根号xy)-y)
已知根号x(根号x-根号y)=根号xy+3y,求(3x-y)分之2x+3倍根号xy-y 的值
已知x>0,y>0,(根号x)×(根号x+2倍根号y)=(根号y)×(6倍根号x+5倍根号y),求 x+根号xy-y
``(x-2倍根号xy+y)(根号x +根号y)
若x>0,y>0,且x-根号xy-2y=0,求y+2倍根号xy分之2x-根号xy的值
已知,x=484,y=2.56,求x+y-2倍根号xy、根号x-根号y
已知当x=8,y=18,求(x+y)/(根号x-根号y)-(2xy)/(x根号y-y根号x)