作业帮计算题,四题,要全,
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/04 21:24:38
计算题,四题,要全,
1题原式=√(m²n^4 +m^4 n²)
=√[m²n²(m²+n²)]
=√(m²n²)·√(m²+n²)
=mn√(m²+n²)
2题 ∵m²/(25n)≥0
∴n﹥0
原式=√[m²/(25n)]
=√[m²×(1/25)×n/n²]
=√m²×√(1/25)×√(1/n²)×√n
=m×1/5 ×1/n×√n
=(m√n)/(5n)
3题∵x﹥0 且 3y/(4x³)≥0
∴y≥0
原式=√[3y/(4x³)]
=√[3xy/(4x^4)]
=√[3xy×1/(2x²)²]
=√(3xy)×√[1/(2x²)]²
=[√(3xy)]/(2x²)
4题原式=√[(x²+y²)²(x²-y²)]
=√(x²+y²)²·√(x²-y²)
=(x²+y²)√(x²-y²)
=√[m²n²(m²+n²)]
=√(m²n²)·√(m²+n²)
=mn√(m²+n²)
2题 ∵m²/(25n)≥0
∴n﹥0
原式=√[m²/(25n)]
=√[m²×(1/25)×n/n²]
=√m²×√(1/25)×√(1/n²)×√n
=m×1/5 ×1/n×√n
=(m√n)/(5n)
3题∵x﹥0 且 3y/(4x³)≥0
∴y≥0
原式=√[3y/(4x³)]
=√[3xy/(4x^4)]
=√[3xy×1/(2x²)²]
=√(3xy)×√[1/(2x²)]²
=[√(3xy)]/(2x²)
4题原式=√[(x²+y²)²(x²-y²)]
=√(x²+y²)²·√(x²-y²)
=(x²+y²)√(x²-y²)