已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y的值
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已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y的值
我是这样做的,老师说不对:[(x²+y²)-(x-y)²+2y(x-y)]/4y=(x²+y²-x²+2xy-y²+2xy-2y²)/4y=(4xy-2y²)/4y=[2y(2x-y)]/4y=二分之一(2x-y)=二分之一乘10=5
我是这样做的,老师说不对:[(x²+y²)-(x-y)²+2y(x-y)]/4y=(x²+y²-x²+2xy-y²+2xy-2y²)/4y=(4xy-2y²)/4y=[2y(2x-y)]/4y=二分之一(2x-y)=二分之一乘10=5
[(x²+y²)-(x-y)²+2y(x-y)]/4y=(x²+y²-x²+2xy-y²+2xy-2y²)/4y
=(4xy-2y²)/4y
=[2y(2x-y)]/4y
=(2x-y)/2
=10/2
=5
对的,可能你的老师同你的做法在步骤上存在不同,但不应该说你是错的.
=(4xy-2y²)/4y
=[2y(2x-y)]/4y
=(2x-y)/2
=10/2
=5
对的,可能你的老师同你的做法在步骤上存在不同,但不应该说你是错的.
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