计算[(x²-5x+6)/(x²-4x+3)]+[(x²-4x+3)/(x²-2

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/09 08:43:20

计算[(x²-5x+6)/(x²-4x+3)]+[(x²-4x+3)/(x²-2x+1)]+[(x²-3x-4)/(1-x²)]

=(x-2)(x-3)/(x-3)(x-1)+(x-3)(x-1)/(x-1)²-(x-4)(x+1)/(x+1)(x-1)
=(x-2)/(x-1)+(x-3)/(x-1)-(x-4)/(x-1)
=(x-2+x-3-x+4)/(x-1)
=(x-1)/(x-1)
=1

计算[(x²-5x+6)/(x²-4x+3)]+[(x²-4x+3)/(x²-2 计算①x²-4／x²-4x+3÷x²+3x+2／x²-x②2x+6／4-4x+x 分式计算x²+2x／x²-6x+9÷x²-4／x²-3x 分式计算：x²+2x／x²-6x+9÷x²-4／x²-3x 计算：2X²-5X+X²+4X-3X²-2 计算：(3/x)+(x/x²-1)-(4/1-x) 计算：(x²-2x-8)分之(2-x)+(3x+6)分之(x+4) 计算： (x+3)(x²-x-2) 计算 (x+3)(x²-x-2) (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 计算x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3= 计算x²-4/x²-x-2 乘以 x²-x/x²+3x+2