已知1/x=1/y=6,则3x-2xy+3y/3xy+x+y=?
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已知1/x=1/y=6,则3x-2xy+3y/3xy+x+y=?
已知1/x+1/y=6,则3x-2xy+3y/3xy+x+y=?
已知1/x+1/y=6,则3x-2xy+3y/3xy+x+y=?
/>∵1/x=1/y=6
∴x=y=1/6
∴(3x-2xy+3y)/(3xy+x+y)
=(3/6-2*1/6*1/6+3/6)/(3*1/6*1/6+1/6+1/6)
上下同乘36
=(18-2+18)/(3+6+6)
=34/15
再问: ��Ǹ����������ˣ���1/x+1/y=1/6
再答: �⣺ 1/x+1/y=6 (x+y)/xy=6 x+y=6xy ��(3x-2xy+3y)/(3xy+x+y) =[3(x+y)-2xy]/[3xy+(x+y)] =(3*6xy-2xy)/(3xy+6xy) =(18xy-2xy)/9xy =16xy/9xy =16/9
再问: ������һ����(3*6xy-2xy)/(3xy+6xy)=(18xy-2xy)/9xy����ô�ó����ģ�
再答: 3*6xy=18xy 2xy+6xy=9xy ��(3*6xy-2xy)/(3xy+6xy)=(18xy-2xy)/9xy
再问: ��Ǹ���ģ�����һ����[3(x+y)-2xy]/[3xy+(x+y)]=(3*6xy-2xy)/(3xy+6xy)
再答: ��x+y=6xy ��3(x+y)=3*6xy x+y=6xy ��[3(x+y)-2xy]/[3xy+(x+y)]=(3*6xy-2xy)/(3xy+6xy)
∴x=y=1/6
∴(3x-2xy+3y)/(3xy+x+y)
=(3/6-2*1/6*1/6+3/6)/(3*1/6*1/6+1/6+1/6)
上下同乘36
=(18-2+18)/(3+6+6)
=34/15
再问: ��Ǹ����������ˣ���1/x+1/y=1/6
再答: �⣺ 1/x+1/y=6 (x+y)/xy=6 x+y=6xy ��(3x-2xy+3y)/(3xy+x+y) =[3(x+y)-2xy]/[3xy+(x+y)] =(3*6xy-2xy)/(3xy+6xy) =(18xy-2xy)/9xy =16xy/9xy =16/9
再问: ������һ����(3*6xy-2xy)/(3xy+6xy)=(18xy-2xy)/9xy����ô�ó����ģ�
再答: 3*6xy=18xy 2xy+6xy=9xy ��(3*6xy-2xy)/(3xy+6xy)=(18xy-2xy)/9xy
再问: ��Ǹ���ģ�����һ����[3(x+y)-2xy]/[3xy+(x+y)]=(3*6xy-2xy)/(3xy+6xy)
再答: ��x+y=6xy ��3(x+y)=3*6xy x+y=6xy ��[3(x+y)-2xy]/[3xy+(x+y)]=(3*6xy-2xy)/(3xy+6xy)
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