2x2+xy-y2-4x+5y-6怎么算,thanks
2x2+xy-y2-4x+5y-6怎么算,thanks
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x
X2+Y2+8X+6Y+25=0 求代数式(x2-4y2/x2+4xy+4y2)-x/x+2y
已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值
分解因式:2x2+xy-y2-4x+5y-6.
x2-(a+b)xy+aby2 x2+4xy-5y2 x2-5x+3 2x2+xy-y2-4x+5y-6
x2-xy-2y2-x+5y-2
x2-xy-2y2-x+5y-2因式分解
因式分解 x2+xy-2y2-x+7y-6
2x2+xy-3y2+x+4y-1因式分解
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是