要求和程序如下,不知道错在哪里,
来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/05/14 08:41:35
要求和程序如下,不知道错在哪里,
Uncle Da is very smart.His IQ was just 0 on his birthday.But it grows 1 everyday.For example,
when Uncle Da is 1 year old,his IQ is 365!
Ziyao big god is smarter then Uncle Da.His IQ was 1 on his birthday,and grows 1 time every day.
For example,when Ziyao is 1 year old,his IQ is 2^365!
Uncle Da's IQ is x when he is n years old.Ziyao's IQ is y when he is m years old.
(We assume that every year is 365 days)
Now a martian want to know how much is (y-x)%400009.
【input format】
Two numbers,n and m.(x,y
Uncle Da is very smart.His IQ was just 0 on his birthday.But it grows 1 everyday.For example,
when Uncle Da is 1 year old,his IQ is 365!
Ziyao big god is smarter then Uncle Da.His IQ was 1 on his birthday,and grows 1 time every day.
For example,when Ziyao is 1 year old,his IQ is 2^365!
Uncle Da's IQ is x when he is n years old.Ziyao's IQ is y when he is m years old.
(We assume that every year is 365 days)
Now a martian want to know how much is (y-x)%400009.
【input format】
Two numbers,n and m.(x,y
虽然不知道哪里错了,但我这有个运行正确的.
int n, m, i, j, sum = 0;
scanf("%d%d", &n, &m);
int x = (365 * n) % 400009 , y = 1;
for (j = 1; j 400009) y -= 400009;
}
printf("%d\n", (y - x + 400009) % 400009);
int n, m, i, j, sum = 0;
scanf("%d%d", &n, &m);
int x = (365 * n) % 400009 , y = 1;
for (j = 1; j 400009) y -= 400009;
}
printf("%d\n", (y - x + 400009) % 400009);
要求和程序如下,不知道错在哪里,
lingo目标规划,程序如下,新手可能格式问题,又不知道错在哪里.
我的理解如下,不知道错在哪里:
matlab程序如下,不知道哪里出错了,说矩阵维数不符合
matlab 程序错误,不知道错在哪里,求高人教怎么修改
matlab蒙特卡罗方法 不知道程序哪里错了,求助
matlab中对一个矩阵所有的数进行循环判断,经过重新计算后存入AQI矩阵中.我的程序如下,不知道哪里错了.
一段matlab程序,不知道哪里不对,
matlab牛顿迭代法生成分形图,编好程序后运行总是出错,但不知道错在哪里,
matlab程序如下,不知道哪出错了
小弟刚学习matlab,编了个程序,但是不知道为什么错误在哪里,
自己写了个程序不知道错在哪?