∫sin^3(x)cos^2(x)dx=
∫sin^3(x)cos^2(x)dx=
∫sin(x) cos^2(x)dx
微积分求解:∫sin^3 (x) cos^2 (x) dx
求积分:∫sin^2 (x) /cos^3 (x) dx
∫ [cos^3(x)]/[sin^2 (x)]dx
∫(cos^3x/sin^2x)dx
定积分∫(-π/2,π/2)(cos^4x+sin^3x)dx=
求解 ∫sin(6x)^3*cos(6x)^8 dx=? 范围[pi/2,0]
∫dx/[sin^2(x/2)cos^2(x/2)]
∫sin^(3)x cos^(3)x dx
∫sin^2(x)cos^2(x)dx
∫dx/cos^2X+4sin^2X