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max=Y3-Y1-Y2;

来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/04/28 00:25:12
max=Y3-Y1-Y2;
Y1=(A(1,1)*M0(1,1)+A(1,2)*M0(1,2)+A(1,3)*M0(1,3)+A(1,4)*M0(1,4)+A(1,5)*M0(1,5)+
A(2,1)*(1+x*0.01)*M0(2,1)+A(2,2)*(1+x*0.01)*M0(2,2)+A(2,3)*(1+2*x*0.01)*M0(2,3)+A(2,4)*(1+2*x*0.01)*M0(2,4)+A(2,5)*(1+2*x*0.01)*M0(2,5)+
A(3,1)*(1+2*x*0.01)*M0(3,1)+A(3,2)*(1+2*x*0.01)*M0(3,2)+A(3,3)*(1+4*x*0.01)*M0(3,3)+A(3,4)*(1+4*x*0.01)*M0(3,4)+A(3,5)*(1+4*x*0.01)*M0(3,5)+
A(4,1)*(1+3*x*0.01)*M0(4,1)+A(4,2)*(1+3*x*0.01)*M0(4,2)+A(4,3)*(1+6*x*0.01)*M0(4,3)+A(4,4)*(1+6*x*0.01)*M0(4,4)+A(4,5)*(1+6*x*0.01)*M0(4,5)+
A(5,1)*(1+4*x*0.01)*M0(6,1)+A(5,2)*(1+4*x*0.01)*M0(5,2)+A(5,3)*(1+8*x*0.01)*M0(5,3)+A(5,4)*(1+8*x*0.01)*M0(5,4)+A(5,5)*(1+8*x*0.01)*M0(5,5)+
A(6,1)*(1+5*x*0.01)*M0(6,1)+A(6,2)*(1+5*x*0.01)*M0(6,2)+A(6,3)*(1+10*x*0.01)*M0(6,3)+A(6,4)*(1+10*x*0.01)*M0(6,4)+A(6,5)*(1+10*x*0.01)*M0(6,5))*75;
Y2=@sum(mm(m):(A(1,m)-B(1,m)+500)+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m)+ A(5,m)-B(5,m))+
(A(1,m)-B(1,m)+500+A(2,m)-B(2,m)+A(3,m)-B(3,m)+A(4,m)-B(4,m)+ A(5,m)-B(5,m)+A(6,m)-B(6,m)));
Y3=@sum(nn(n):(B(n,1)+B(n,2)+B(n,3)+B(n,4)+B(n,5))*2250);
@for(mm(m):A(1,m)-B(1,m)+500
解释什么? 这个都需要你自己去看 只要知道基本的语法熟悉线性规划就能看懂 否则说了也没用 自己找个教程看看吧