the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)
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the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)and A(1,0),meet at the point N
find the coordinates of N calculate the area of triangle OAN
find the coordinates of N calculate the area of triangle OAN
point N is(1/5,2/5) the area is 1/5
according to the normal at the points O(0,0) and A(0,1),we can get two line,they are y=2x and y=-1/2(x-1),thus,we can get x=1/5,y=2/5,this is point N,so the area=1/2*2/5=1/5
OR you can tell your teacher :i am chinese,this is so easy,N is(1/5,2/5) the area is 1/5
再问: 题目什么意思 normal怎么用
再答: normal是法线
according to the normal at the points O(0,0) and A(0,1),we can get two line,they are y=2x and y=-1/2(x-1),thus,we can get x=1/5,y=2/5,this is point N,so the area=1/2*2/5=1/5
OR you can tell your teacher :i am chinese,this is so easy,N is(1/5,2/5) the area is 1/5
再问: 题目什么意思 normal怎么用
再答: normal是法线
the normal to the curve 2y=3x^3-7x^2+4x,at the points O(0,0)
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