若0<x<π/2,则arccos[cos﹙π/2+x﹚]+arcsin[sin﹙π+x﹚]等于﹙ ﹚A.π/2 B.﹣π
若0<x<π/2,则arccos[cos﹙π/2+x﹚]+arcsin[sin﹙π+x﹚]等于﹙ ﹚A.π/2 B.﹣π
证明恒等式:arcsin x+arccos x=π/2(-1≦x≦1)
.已知sin x+cos x= (0≤x<π),则tan x的值等于
sin(x) cos(x) tan(x) cot(x) sec(x) csc(x) arcsin(x) arccos(x
已知tan(π/4-x)=﹣1/3,求[sin²﹙x+π/4﹚]/[2cos²x+sin2x]的值
已知向量a=[cos(3x/2),sin(3x/2)],b=[cos(x/2),-sin(x/2),]且x∈[0,π/2
已知向量a=(cos(3x/2),sin(3x/2)),b=(cos(x/2),-sin(x/2)),且x∈[0,π/2
设向量a=(cos(x/2),sin(x/2)),向量b=(sin(3x/2),cos(3x/2)),x∈[0,π/2]
已知向量a=(cos 3/2x,sin 3/2x),b=(cos x/2,-sin x/2),x∈[0,π/2]
已知向量a=(cos 3/2 x,sin 3/2 x),b=(cos x/2,-sin x/2),x属于[0,π/2],
已知向量a等于(cosx,cosx),向量b等于(2cos,sin(π-x))若f(x)等于ab+1,求函数f(x)的解
arcsin|x|>arccos|x|